Typecho 根据文章阅读数降序排序输出“热门文章”列表
要想实现标题中的功能,sql 语句可以这样写
select views, cid, from_unixtime(created, '%Y-%m-%d %H:%m:%s') as created_time, title, commentsNum from typecho_contents where type='post' and status='publish' order by views desc;
现在通过在 typecho 博客上实现,并在 归档页面 展示。下面展示我的方法。
functions.php
中增加以下函数
/**
* 根据文章阅读数排序的热门发布文章
*/
function mostViewsPosts()
{
$archive = Typecho_Widget::widget('Widget_Archive');
// $hotNums = 5; //热门文章数
// $minViews = 10; //最低阅读量
$db = Typecho_Db::get();
$select = $db->select()->from('table.contents')
->where('table.contents.type = ?', 'post')
->where('table.contents.status = ?', 'publish');
//->limit($hotNums);
$select->order("table.contents.views", Typecho_Db::SORT_DESC);
$rows = $db->fetchAll($select);
foreach ($rows as $row) {
$mostViewsPosts[] = $archive->filter($row);
}
return $mostViewsPosts;
}
page-archives.php
中增加如下代码(用于 html 显示)
<hr />
<article class="post">
<?php $HotPosts = mostViewsPosts(); ?>
<?php if (count($HotPosts) > 1) : ?>
<div class="mostViewsPosts">
<ul>
<h1 class="post-title">按照阅读数降序排序的热门文章</h1>
<?php $loopItem = 1; ?>
<?php foreach ($HotPosts as $v) { ?>
<a class="title" title="<?= $v['title']; ?>" href="<?= $v['permalink']; ?>">
<li>
<div><?= $v['title']; ?></div>
</li>
</a>
<span class="seqNumber">seq is <?= $loopItem++; ?></span><span class="views"> | <?= $v['views']; ?> 次阅读</span><span class="postTime"> | 发布于 <?= date('Y-m-d H:m:s', $v['created']); ?></span><span class="commentsNum"> | 已有 <?= $v['commentsNum']; ?> 条评论</span>
<br />
<br />
<?php } ?>
</ul>
</div>
<?php endif; ?>
</article>
tyle.min.css
中增加样式
.mostViewsPosts .title {
color: black;
}
.mostViewsPosts .seqNumber {
color: #FF9900;
}
.mostViewsPosts .views {
color: red;
}
.mostViewsPosts .postTime {
color: green;
}
.mostViewsPosts .commentsNum {
color: blue;
}
a {
color: black;
text-decoration: none;
}
最终界面预览如下 归档页面